Submission #1971565

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Source Code Expand

import math
import sys

n = int(input())
s = int(input())

def f(b, n):
    if n == 0:
        return 0
    return f(b, n//b) + n % b

if s > n:
    print(-1)
    sys.exit(0)

sn = math.ceil(math.sqrt(n))
for i in range(2, sn+1):
    if f(i, n) == s:
        print(i)
        sys.exit(0)

for i in range(1, sn+1):
    if (n - s) % i == 0:
        b = (n-s)//i + 1
        if b >= 2 and f(b, b * i + n%b) == s:
            print(b)
            sys.exit(0)
if s == n:
    print(n+1)
else:
    print(-1)

Submission Info

Judge Result